document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=98>Question 98</A>: <I><SPAN STYLE=\"word-break: break-all;\"> In 7 years, Maria will be four times as old as Angelica will be then. The sum of their ages now is 71. How old will each of them be in 5 years? </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #428678 by </B><A HREF=/tutors/aboutme.mpl?userid=srirajdhaks><B>srirajdhaks(1)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=srirajdhaks><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=428678\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> (Name)              (Age now)            (Age after 5 years)\r<BR>\n" );
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document.write( "(Maria)              (7+4x)               (7+4x+5 = 12+4x)\r<BR>\n" );
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document.write( "(Angelica)           (7+x)                (7+x+5 = 12+x)\r<BR>\n" );
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document.write( "The sum of their ages now is 71\r<BR>\n" );
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document.write( "12+4x+12+x =71<BR>\n" );
document.write( "24+5x =71<BR>\n" );
document.write( "5x =71-24<BR>\n" );
document.write( "5x =47<BR>\n" );
document.write( "x =47/5 =9.4\r<BR>\n" );
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document.write( "Maria : 7+4(9.4) =44.6<BR>\n" );
document.write( "Angelica : 7+9.4 =16.4\r<BR>\n" );
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document.write( "Verify the answer:\r<BR>\n" );
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document.write( "12+4(9.4)+12+9.4 =71<BR>\n" );
document.write( "71 =71 </SPAN>\n" );
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