document.write( "Question 695868: solve over the set of complex numbers
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document.write( "(x+5)^2=-36 (given)
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document.write( "if I work it out I get x^2-10x+61=0
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document.write( "but now what, it won't foil,
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document.write( "x^2-10x+25=-36
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document.write( "x^2-10x+25= -61+25 completing the square gets me right back where I started... \n" );
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Algebra.Com's Answer #428660 by KMST(5328)![]() ![]() You can put this solution on YOUR website! To solve a quadratic equation for complex solutions, you work just as you do for real solutions, \n" ); document.write( "except that you go further than the point where you would say the equation has no real solutions, \n" ); document.write( "because a negative number cannot be the square of a real number, \n" ); document.write( "but it is the square of a complex number. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "The only real (and complex) numbers that squared equal \n" ); document.write( "The only complex numbers that squared equal \n" ); document.write( "So, the only complex numbers that squared equal \n" ); document.write( "So, either \n" ); document.write( "or |