document.write( "Question 695750: Write down the period of the graph of y = 3/(2+cos^2 2x) (that's 2 plus cosine squared 2x in case it isn't clear) and also the coordinates of a maximum value of y.
\n" ); document.write( "Okay so I've always been confused about the period thing. The equation is 2pi/b, where the b value is the frequency, but I'm not sure how to use that. And also, to find the coordinates of the max, you take the derivative and set it equal to 0 and find the values that make that true and then test for if it's a minimum or maximum, correct? \n" ); document.write( "

Algebra.Com's Answer #428641 by stanbon(75887) $\"\"$ $\"About$

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Write down the period of the graph of y = 3/(2+cos^2 2x) (that's 2 plus cosine squared 2x in case it isn't clear) and also the coordinates of a maximum value of y.
\n" ); document.write( "Okay so I've always been confused about the period thing. The equation is 2pi/b, where the b value is the frequency, but I'm not sure how to use that. And also, to find the coordinates of the max, you take the derivative and set it equal to 0 and find the values that make that true and then test for if it's a minimum or maximum, correct?
\n" ); document.write( "------
\n" ); document.write( "The (2pi)/b for the period relates to f(x) = acos(2x+b)=c, not to
\n" ); document.write( "y = 3/(2+cos^2 2x).
\n" ); document.write( "----
\n" ); document.write( "What you say about the derivative to find the max or min is true.
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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