document.write( "Question 695748: A boy is biking home from school at 9 miles per hour. He is 10 minutes ahead of his sister who is biking at 12 miles per hour. How long will it take for the sister to catch up with her brother? \r
\n" ); document.write( "\n" ); document.write( "I tried using the equation 12x=9x + 1/6 (because 10 minutes is 1/6 of an hour) the answer I got was 1/9 but it wasn't one of the choices.
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Algebra.Com's Answer #428640 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
Start a stopwatch when his sister leaves.
\n" ); document.write( "In miles, the boy has a \"+9%2A%28+1%2F6%29+=+1.5+\" mi head start
\n" ); document.write( "Let \"+d+\" = the distance the sister has to travel until
\n" ); document.write( "she catches her brother
\n" ); document.write( "Let \"+t+\" = time on stopwatch when she catches him
\n" ); document.write( "--------------------
\n" ); document.write( "Sister's equation:
\n" ); document.write( "(1) \"+d+=+12t+\"
\n" ); document.write( "Brother's equation:
\n" ); document.write( "(2) \"+d+-+1.5+=+9t+\"
\n" ); document.write( "------------------
\n" ); document.write( "Substitute (1) into (2)
\n" ); document.write( "(2) \"+12t+-+1.5+=+9t+\"
\n" ); document.write( "(2) \"+3t+=+1.5+\"
\n" ); document.write( "(2) \"+t+=+.5+\"
\n" ); document.write( "It takes her 1/2 hr to catch her brother
\n" ); document.write( "check:
\n" ); document.write( "(1) \"+d+=+12%2A.5+\"
\n" ); document.write( "(1) \"+d+=+6+\"
\n" ); document.write( "and
\n" ); document.write( "(2) \"+d+-+1.5+=+9%2A.5+\"
\n" ); document.write( "(2) \"+d+=+4.5+%2B+1.5+\"
\n" ); document.write( "(20 \"+d+=+6+\"
\n" ); document.write( "OK\r
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