document.write( "Question 695724: Please help me solve this equation : Paula rows a boat 6 miles upstream in 3 hours. She returns 6 miles downstream in 2 hours. What is the rate at which Paula rows in still water? What is the rate of the current? \n" ); document.write( "

Algebra.Com's Answer #428628 by mananth(16949) $\"\"$ $\"About$

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canoe speed speed =x mph
\n" ); document.write( "current speed =y mph
\n" ); document.write( "against current 3 hours
\n" ); document.write( "with current 2 hours
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\n" ); document.write( "Distance with current 6 miles distance against current 6
\n" ); document.write( "t=d/r against current (x-y)
\n" ); document.write( "6.00 / ( x - y )= 3.00
\n" ); document.write( "
\n" ); document.write( "3.00 x - -3.00 y = 6.00 ....................1
\n" ); document.write( "with current (x+y)
\n" ); document.write( "6.00 / ( x + y )= 2.00
\n" ); document.write( "2.00 ( x + y ) = 6.00
\n" ); document.write( "2.00 x + 2.00 y = 6.00 ...............2
\n" ); document.write( "Multiply (1) by 2.00
\n" ); document.write( "Multiply (2) by 3.00
\n" ); document.write( "we get
\n" ); document.write( "6.00 x + -6.00 y = 12.00
\n" ); document.write( "6.00 x + 6.00 y = 18.00
\n" ); document.write( "12.00 x = 30.00
\n" ); document.write( "/ 12.00
\n" ); document.write( "x = 2.5 mph
\n" ); document.write( "
\n" ); document.write( "plug value of x in (1) y
\n" ); document.write( "3 x -3 y = 6
\n" ); document.write( "7.5 -3 -7.5 = 6
\n" ); document.write( "-3 y = 6
\n" ); document.write( "-3 y = -1.5 mph
\n" ); document.write( " y = 0.5
\n" ); document.write( "canoe speed 2.5 mph
\n" ); document.write( "current 0.5 mph
\n" ); document.write( " \n" ); document.write( "

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