document.write( "Question 695712: what are five points that i can graph for the equation y=x^2+4 (vertex form)\r
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Algebra.Com's Answer #428620 by Edwin McCravy(20056) $\"\"$ $\"About$

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what are five points that i can graph for the equation y=x^2+4 (vertex form)
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document.write( "The vertex form is\r\n" );
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document.write( "y = 1(x-0)²+4\r\n" );
document.write( "y = a(x-h)²+k, so the vertex is (h,k) = (0.4)\r\n" );
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document.write( "(-3,13), (-2,8), (-1,5), (0,4), (1,5), (2,8), (3,13)\r\n" );
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\n" ); document.write( "and for the equation
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\n" ); document.write( "y=2x^2+6x=12
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document.write( "You mistyped an = sign for either a + or a - sign\r\n" );
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document.write( "If you meant a + sign, y=2x²+6x+12\r\n" );
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document.write( "(-4,20), (-3,12), (-2,8), (-1.5,7.5), (-1,-8), (0,12), (1,20)\r\n" );
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document.write( "If you meant a - sign, y=2x²+6x-12 \r\n" );
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document.write( "(-5,8), (-4,-4), (-3,-12), (-2,-16), (-1.5,-16.5), (-1,-16), \r\n" );
document.write( "(0,-12), (1,-4), (2,8)\r\n" );
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document.write( "Edwin

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