document.write( "Question 695644: Please help me solve by completing the squares:\r
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Algebra.Com's Answer #428582 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! (x^2) - (6x) = (27) \n" ); document.write( "----- \n" ); document.write( "x^2 - 6x + (6/2)^2 = 27 + (6/2)^2 \n" ); document.write( "-------- \n" ); document.write( "x^2 -6x + 9 = 27 + 9 \n" ); document.write( "-------- \n" ); document.write( "(x-3)^2 = 36 \n" ); document.write( "---- \n" ); document.write( "x-3 = 6 or x - 3 = -3 \n" ); document.write( "x = 9 or x = 0 \n" ); document.write( "===============================\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( "(2x^2) - (9x) + (9) = (0) \n" ); document.write( "----- \n" ); document.write( "2[x^2 - (9/2)x + ?] = -9 + 2? \n" ); document.write( "----- \n" ); document.write( "2[x^2 -(9/2)x + (9/4)^2] = -9 + 2(9/4)^2 \n" ); document.write( "----- \n" ); document.write( "2(x-(3/2))^2 = [-9*16 + 162]/16 \n" ); document.write( "----- \n" ); document.write( "2(x-(3/2))^2 = 1/2 \n" ); document.write( "---- \n" ); document.write( "(x-(3/2))^2 = 1/4 \n" ); document.write( "---- \n" ); document.write( "x-(3/2) = 1/2 or x-(3/2) = -1/2 \n" ); document.write( "------- \n" ); document.write( "x = 2 or x = 1 \n" ); document.write( "===================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H.\r \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |