document.write( "Question 695513: how would you solve:
\n" ); document.write( " log(x+1)+(x-7)=log(10x+10)
\n" ); document.write( "this is what i did so far:
\n" ); document.write( "a. log(x+1)(x-7)=log(10x+10)
\n" ); document.write( "b.log (x+1)(x+7)/(10x+10)---> is this correct...now am stuck i don't know the next step or if i even did it correctly \r
\n" ); document.write( "\n" ); document.write( "Thank you in advance!
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Algebra.Com's Answer #428518 by mouk(232)\"\" \"About 
You can put this solution on YOUR website!
You are correct upto (a)\r
\n" ); document.write( "\n" ); document.write( "If \"+log%28%28x%2B1%29%28x-7%29%29=log%2810x%2B10%29+\" then
\n" ); document.write( "\"+%28x%2B1%29%28x-7%29+=+10x%2B10+\" because \"+logA=logB+\" if and only if \"+A=B+\"
\n" ); document.write( "which reduces to a quadratic:
\n" ); document.write( "\"+x%5E2-6x-7=10x%2B10+\"
\n" ); document.write( "\"+x%5E2-16x-17+=+0+\"
\n" ); document.write( "\"+%28x-17%29%28x%2B1%29+=+0\" so \"+x=-1+\" or \"+x=17+\"
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