document.write( "Question 695491: Solve 1-log(3x+1)=log(x-2)\r
\n" ); document.write( "\n" ); document.write( "log base =10
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Algebra.Com's Answer #428506 by lwsshak3(11628)\"\" \"About 
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Solve 1-log(3x+1)=log(x-2)
\n" ); document.write( "log base =10
\n" ); document.write( "1-log(3x+1)=log(x-2)
\n" ); document.write( "1=log(x-2)+log(3x+1)
\n" ); document.write( "log(10)=log[(x-2)(3x+1)]
\n" ); document.write( "(x-2)(3x+1)=10
\n" ); document.write( "3x^2-5x-2=10
\n" ); document.write( "3x^2-5x-12=0
\n" ); document.write( "(x-3)(3x+4)=0
\n" ); document.write( "x=3
\n" ); document.write( "or
\n" ); document.write( "x=-4/3 (reject, (x-2)>0
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