document.write( "Question 695491: Solve 1-log(3x+1)=log(x-2)\r
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document.write( "log base =10 \n" );
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Algebra.Com's Answer #428506 by lwsshak3(11628)![]() ![]() ![]() You can put this solution on YOUR website! Solve 1-log(3x+1)=log(x-2) \n" ); document.write( "log base =10 \n" ); document.write( "1-log(3x+1)=log(x-2) \n" ); document.write( "1=log(x-2)+log(3x+1) \n" ); document.write( "log(10)=log[(x-2)(3x+1)] \n" ); document.write( "(x-2)(3x+1)=10 \n" ); document.write( "3x^2-5x-2=10 \n" ); document.write( "3x^2-5x-12=0 \n" ); document.write( "(x-3)(3x+4)=0 \n" ); document.write( "x=3 \n" ); document.write( "or \n" ); document.write( "x=-4/3 (reject, (x-2)>0 \n" ); document.write( " \n" ); document.write( " |