document.write( "Question 695427: Question:
\n" ); document.write( "A mixture of 20% acid and 50% acid must be mixed together to obtain 100mL of 44% acid solution. How much of each acid will be required?\r
\n" ); document.write( "\n" ); document.write( "Answer:
\n" ); document.write( "Let x represent amount (in mL) of 20% acid required
\n" ); document.write( "Let y represent amount (in mL) of 50% acid required\r
\n" ); document.write( "\n" ); document.write( "100 = x + y
\n" ); document.write( "44 = 0.2x + 0.5y\r
\n" ); document.write( "\n" ); document.write( "I got the right answer
\n" ); document.write( "x = 20
\n" ); document.write( "y = 80\r
\n" ); document.write( "\n" ); document.write( "I just don't understand why 44 isn't changed into 0.44 and the other numbers are. Would you mind explaining?
\n" ); document.write( "

Algebra.Com's Answer #428503 by MathTherapy(10552)\"\" \"About 
You can put this solution on YOUR website!

\n" ); document.write( "Question:
\n" ); document.write( "A mixture of 20% acid and 50% acid must be mixed together to obtain 100mL of 44% acid solution. How much of each acid will be required?\r
\n" ); document.write( "\n" ); document.write( "Answer:
\n" ); document.write( "Let x represent amount (in mL) of 20% acid required
\n" ); document.write( "Let y represent amount (in mL) of 50% acid required\r
\n" ); document.write( "\n" ); document.write( "100 = x + y
\n" ); document.write( "44 = 0.2x + 0.5y\r
\n" ); document.write( "\n" ); document.write( "I got the right answer
\n" ); document.write( "x = 20
\n" ); document.write( "y = 80\r
\n" ); document.write( "\n" ); document.write( "I just don't understand why 44 isn't changed into 0.44 and the other numbers are. Would you mind explaining?\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "x + y = 100 ----- eq (i)
\n" ); document.write( "0.2x + 0.5y = .44(100) ------ 0.2x + 0.5y = 44\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Do you now see how 44 was derived?\r
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Send comments and “thank-yous” to “D” at MathMadEzy@aol.com
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