document.write( "Question 695260: A battleship started at 7:00 AM on a 500 mile voyage on a special mission but was brought to a full stop an hour after starting for military reasons, delaying it for a full hour, after which it was ordered to proceed at a reduced velocity equivalent to 75% of its original speed. This ship arrived at its destination 3 ¾ hr. after the scheduled time. Determine the original speed of the battleship. \n" ); document.write( "
Algebra.Com's Answer #428490 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! A battleship started at 7:00 AM on a 500 mile voyage on a special mission \n" ); document.write( " but was brought to a full stop an hour after starting for military reasons, \n" ); document.write( " delaying it for a full hour, after which it was ordered to proceed at a reduced \n" ); document.write( " velocity equivalent to 75% of its original speed. \n" ); document.write( " This ship arrived at its destination 3 ¾ hr. after the scheduled time. \n" ); document.write( " Determine the original speed of the battleship. \n" ); document.write( ": \n" ); document.write( "Let s = original speed of the ship \n" ); document.write( ": \n" ); document.write( "change 3 \n" ); document.write( ": \n" ); document.write( " \n" ); document.write( ": \n" ); document.write( "Write a distance equation of the actual voyage \n" ); document.write( ": \n" ); document.write( "dist at normal speed + distance at reduced speed = 500 mi \n" ); document.write( "1s + .75s( \n" ); document.write( "1s + .75s( \n" ); document.write( "1s + (.75s( \n" ); document.write( "1s + 375 + 2.0625s = 500 \n" ); document.write( "3.0625s = 500 - 375 \n" ); document.write( "3.0625s = 125 \n" ); document.write( "s = 125/3.0625 \n" ); document.write( "s = 40.8 mph (or knots if nautical miles are used) \n" ); document.write( ": \n" ); document.write( ": \n" ); document.write( "See if that checks out \n" ); document.write( "normal time: 500/40.8 = 12.25 hrs \n" ); document.write( "Additional time required 3.75 hrs \n" ); document.write( "------------------------------------ \n" ); document.write( "Actual time of the voyage: 16 hrs \n" ); document.write( ": \n" ); document.write( "(500-40.8) = 459.2 mi at 3/4 speed which is .75(40.8) = 30.6 knots \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " |