document.write( "Question 695260: A battleship started at 7:00 AM on a 500 mile voyage on a special mission but was brought to a full stop an hour after starting for military reasons, delaying it for a full hour, after which it was ordered to proceed at a reduced velocity equivalent to 75% of its original speed. This ship arrived at its destination 3 ¾ hr. after the scheduled time. Determine the original speed of the battleship. \n" ); document.write( "
Algebra.Com's Answer #428490 by ankor@dixie-net.com(22740)\"\" \"About 
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A battleship started at 7:00 AM on a 500 mile voyage on a special mission
\n" ); document.write( " but was brought to a full stop an hour after starting for military reasons,
\n" ); document.write( " delaying it for a full hour, after which it was ordered to proceed at a reduced
\n" ); document.write( " velocity equivalent to 75% of its original speed.
\n" ); document.write( " This ship arrived at its destination 3 ¾ hr. after the scheduled time.
\n" ); document.write( " Determine the original speed of the battleship.
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\n" ); document.write( "Let s = original speed of the ship
\n" ); document.write( ":
\n" ); document.write( "change 3\"3%2F4\" to 3.75 hrs
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\n" ); document.write( "\"500%2Fs\" = time of voyage with no stops or change in speed
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\n" ); document.write( "Write a distance equation of the actual voyage
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\n" ); document.write( "dist at normal speed + distance at reduced speed = 500 mi
\n" ); document.write( "1s + .75s(\"500%2Fs\" - 1 + 3.75) = 500
\n" ); document.write( "1s + .75s(\"500%2Fs\" + 2.75) = 500
\n" ); document.write( "1s + (.75s(\"500%2Fs\") + .75s(2.75) = 500
\n" ); document.write( "1s + 375 + 2.0625s = 500
\n" ); document.write( "3.0625s = 500 - 375
\n" ); document.write( "3.0625s = 125
\n" ); document.write( "s = 125/3.0625
\n" ); document.write( "s = 40.8 mph (or knots if nautical miles are used)
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\n" ); document.write( "See if that checks out
\n" ); document.write( "normal time: 500/40.8 = 12.25 hrs
\n" ); document.write( "Additional time required 3.75 hrs
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\n" ); document.write( "Actual time of the voyage: 16 hrs
\n" ); document.write( ":
\n" ); document.write( "(500-40.8) = 459.2 mi at 3/4 speed which is .75(40.8) = 30.6 knots
\n" ); document.write( "\"459.2%2F30.6\" = 15 hr + 1 hr at normal speed = 16 hrs, the actual time
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