document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=695373>Question 695373</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Find the equation of a line y-intercept of 2/3 and.slope of -5. Then graph. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #428457 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=428457\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> y intercept = 2/3<BR>\n" );
document.write( "so the interception point on y axis = (0,(2/3))\r<BR>\n" );
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document.write( "slope = -5\r<BR>\n" );
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document.write( "Using the slope point form of equation\r<BR>\n" );
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document.write( "y-y1=m(x-x1)\r<BR>\n" );
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document.write( "where (x1,y1) are the co ordinates and m is the slope\r<BR>\n" );
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document.write( "y-(2/3) = -5(x-0)\r<BR>\n" );
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document.write( "y-(2/3) =-5x\r<BR>\n" );
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document.write( "y= -5x+(2/3)  ( slope intercept form)\r<BR>\n" );
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document.write( "Multiply by 3\r<BR>\n" );
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document.write( "3y=2-15x<BR>\n" );
document.write( "15x+3y=2 ( standard form)\r<BR>\n" );
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document.write( " </SPAN>\n" );
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