document.write( "Question 695310: how do you factor 5n^3-28n^2-49n completely? \n" ); document.write( "
Algebra.Com's Answer #428415 by stanbon(75887)\"\" \"About 
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factor 5n^3-28n^2-49n completely
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\n" ); document.write( "= n(5n^2 - 28n - 49)
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\n" ); document.write( "= n(n-7)(5n+7)
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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