document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=695180>Question 695180</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3x+7=x-4 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #428358 by </B><A HREF=/tutors/aboutme.mpl?userid=Simnepi><B>Simnepi(216)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Simnepi><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Simnepi><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=428358\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Subtract x from both sides of the equation\r<BR>\n" );
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document.write( "3x+7 (- x) = x-4 (- x)  (this eliminates the x from the right hand side of the equal sign)<BR>\n" );
document.write( "so now you have<BR>\n" );
document.write( "2x+7 = -4<BR>\n" );
document.write( "now subtract 7 from both sides of the equation<BR>\n" );
document.write( "2x+7 (- 7) = -4 (- 7) (this eliminates the plus 7 on the left hand side)<BR>\n" );
document.write( "so now you have<BR>\n" );
document.write( "2x = -11<BR>\n" );
document.write( "dividing by 2 on both sides<BR>\n" );
document.write( "2x/2 = -11/2 this gets rid of the number in front of the x (the coefficient of x) just leaving x on one side and a number on the other<BR>\n" );
document.write( "x = -5.5<BR>\n" );
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