document.write( "Question 695157: If y varies dirctly as x, and x = 9 when y = 15, find y when x = 33. I think the formula is Y=KX. This is the way I did it.\r
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\n" ); document.write( "\n" ); document.write( "Y=KX
\n" ); document.write( "15=K(9)
\n" ); document.write( "15/9=K (divided both sides by 9)
\n" ); document.write( "1.667= K\r
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\n" ); document.write( "\n" ); document.write( "Y=KX
\n" ); document.write( "Y=1.667 times 33
\n" ); document.write( "y=55.003\r
\n" ); document.write( "\n" ); document.write( "Is this done right?
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Algebra.Com's Answer #428347 by pmatei(79)\"\" \"About 
You can put this solution on YOUR website!
Very good. You did everything correctly.\r
\n" ); document.write( "\n" ); document.write( "The only thing I would recommend is that you keep \"k=15%2F9=5%2F3\" instead of decimal number.\r
\n" ); document.write( "\n" ); document.write( "When multiplying \"k=5%2F3\" with \"x=33\", you get \"y=%285%2F3%29%2A33=55\". \r
\n" ); document.write( "\n" ); document.write( "The slight difference between your answer 55.003 and my answer 55 comes from rounding up the fraction \"5%2F3\" to 1.667. Keeping everything as fractions, always gives you the correct answers, where decimals might be a little bit off.
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