document.write( "Question 695141: When a ball is kicked in the air, its height in meter above the ground can be modeled by h(t)= -4.9t^2 + 14.7t and the distance it travels can be modeled by d(t)=16t where t is the time in seconds.
\n" );
document.write( "a. How long is the ball in the air
\n" );
document.write( "b. How far does it travel before it hits the ground
\n" );
document.write( "c. What is the maximum height of the ball
\n" );
document.write( "Can you please help?
\n" );
document.write( "Thank you! \n" );
document.write( "
Algebra.Com's Answer #428332 by stanbon(75887)![]() ![]() ![]() You can put this solution on YOUR website! When a ball is kicked in the air, its height in meter above the ground can be modeled by h(t)= -4.9t^2 + 14.7t and the distance it travels can be modeled by d(t)=16t where t is the time in seconds. \n" ); document.write( "a. How long is the ball in the air \n" ); document.write( "The ball starts on the ground and ends up on the ground. \n" ); document.write( "It's height on the ground is zero. \n" ); document.write( "Solve: -4.9t^2+14.7t = 0 \n" ); document.write( "t(-4.9t+14.7) = 0 \n" ); document.write( "t = 0 and t = 14.7/4.9 = 3 seconds \n" ); document.write( "Ans: The ball in in the air for 3 seconds \n" ); document.write( "------------------------------------------------- \n" ); document.write( "b. How far does it travel before it hits the ground \n" ); document.write( "Ans: 3 meters \n" ); document.write( "----------------------------------- \n" ); document.write( "c. What is the maximum height of the ball \n" ); document.write( "Vertex occurs at t = -b/(2a) = -14.7/(2*-4.9) = 3/2 \n" ); document.write( "h(3/2) = -4.9(3/2)^2 + 14.7(3/2) = 11.025 meters (maximum height) \n" ); document.write( "======================== \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "======================== \n" ); document.write( " \n" ); document.write( " |