document.write( "Question 694952:  1/2x+1/3y=-1/2\r
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document.write( "1/2x+3y=15/2\r
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document.write( "solve by substitution method \n" );
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Algebra.Com's Answer #428303 by Ave(106)    You can put this solution on YOUR website! 1/2x+1/3y=-1/2 \n" ); document.write( "1/2x+3y=15/2 \n" ); document.write( "pick one equations and solve for x or y \n" ); document.write( "1/2x+3y=15/2 multiply by 2 to get rid of fractions \n" ); document.write( "x+6y=15 \n" ); document.write( "x=-6y+15 \n" ); document.write( "Now plug in the value of x into the other equations \n" ); document.write( "1/2(-6y+15)+1/3y=-1/2 multiply by 6 to get rid of fractions \n" ); document.write( "3(-6y+15)+2y=-3 \n" ); document.write( "-18y+45+2y=-3 \n" ); document.write( "-16y=-48 \n" ); document.write( "y=3 \n" ); document.write( "Now plug the value of y back in, to find x \n" ); document.write( "x=-6(3)+15 \n" ); document.write( "x=-18+15 \n" ); document.write( "x=-3\r \n" ); document.write( "\n" ); document.write( "(-3, 3) \n" ); document.write( "  |