document.write( "Question 694952: 1/2x+1/3y=-1/2\r
\n" ); document.write( "\n" ); document.write( "1/2x+3y=15/2\r
\n" ); document.write( "\n" ); document.write( "solve by substitution method
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Algebra.Com's Answer #428303 by Ave(106)\"\" \"About 
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1/2x+1/3y=-1/2
\n" ); document.write( "1/2x+3y=15/2
\n" ); document.write( "pick one equations and solve for x or y
\n" ); document.write( "1/2x+3y=15/2 multiply by 2 to get rid of fractions
\n" ); document.write( "x+6y=15
\n" ); document.write( "x=-6y+15
\n" ); document.write( "Now plug in the value of x into the other equations
\n" ); document.write( "1/2(-6y+15)+1/3y=-1/2 multiply by 6 to get rid of fractions
\n" ); document.write( "3(-6y+15)+2y=-3
\n" ); document.write( "-18y+45+2y=-3
\n" ); document.write( "-16y=-48
\n" ); document.write( "y=3
\n" ); document.write( "Now plug the value of y back in, to find x
\n" ); document.write( "x=-6(3)+15
\n" ); document.write( "x=-18+15
\n" ); document.write( "x=-3\r
\n" ); document.write( "\n" ); document.write( "(-3, 3)
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