document.write( "Question 694986: find 2 consecutive integers such that the larger is nine more than twice the smaller \n" ); document.write( "
Algebra.Com's Answer #428286 by MathTherapy(10555)\"\" \"About 
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\n" ); document.write( "find 2 consecutive integers such that the larger is nine more than twice the smaller\r
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\n" ); document.write( "\n" ); document.write( "Let the smaller integer be S
\n" ); document.write( "Then larger = S + 1\r
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\n" ); document.write( "\n" ); document.write( "Therefore, S + 1 = 2S + 9\r
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\n" ); document.write( "\n" ); document.write( "S - 2S = 9 - 1\r
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\n" ); document.write( "\n" ); document.write( "- S = 8\r
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\n" ); document.write( "\n" ); document.write( "S, or smaller number = \"8%2F-1\", or \"highlight_green%28-+8%29\"\r
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\n" ); document.write( "\n" ); document.write( "Larger integer = - 8 + 1, or \"highlight_green%28-+7%29\"\r
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\n" ); document.write( "\n" ); document.write( "You can do the check!!\r
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\n" ); document.write( "\n" ); document.write( "Send comments and “thank-yous” to “D” at MathMadEzy@aol.com
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