document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=694828>Question 694828</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Given that 2log to the base y of x =3 find the relation involving x and y </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #428269 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=428269\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Given that 2log to the base y of x =3 find the relation involving x and y<BR>\n" );
document.write( "----<BR>\n" );
document.write( "2logy(x) = 3<BR>\n" );
document.write( "-----<BR>\n" );
document.write( "logy(x^2) = 3<BR>\n" );
document.write( "---<BR>\n" );
document.write( "y^3 = x^2<BR>\n" );
document.write( "----<BR>\n" );
document.write( "y = x^(2/3)<BR>\n" );
document.write( "===================<BR>\n" );
document.write( "Cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
document.write( "============= </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );