document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=694925>Question 694925</A>: <I><SPAN STYLE=\"word-break: break-all;\"> how do you solve this linear system by using substitution\r<BR>\n" );
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document.write( "x=6-4y<BR>\n" );
document.write( "2x-3y=1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #428246 by </B><A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><B>jim_thompson5910(35256)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=jim_thompson5910><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=428246\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Hint:\r<BR>\n" );
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document.write( "2x-3y=1\r<BR>\n" );
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document.write( "2(6-4y)-3y=1 ... plug in x=6-4y\r<BR>\n" );
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document.write( "12 - 8y - 3y = 1\r<BR>\n" );
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document.write( "12 - 11y = 1\r<BR>\n" );
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document.write( "Keep going to solve for y. Then use this value of y to find the value of x. </SPAN>\n" );
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