document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=694549>Question 694549</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The city of Ottawa has provided 300 meters of rope to enclose a rectangular swimming area along the shore of the Mooney Bay Beach. What is the maximum area that can be enclosed and the dimensions of the maximum area.\r<BR>\n" );
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document.write( "Can you please help me out I really don't understand? Thanks in advance I appreciate it. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #428243 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=428243\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The city of Ottawa has provided 300 meters of rope to enclose a rectangular swimming area along the shore of the Mooney Bay Beach. What is the maximum area that can be enclosed and the dimensions of the maximum area. <BR>\n" );
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document.write( "Let L = the length of the rectangle<BR>\n" );
document.write( "Let W = the width<BR>\n" );
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document.write( "Only 3 sides are required so the perimeter with 300 m of rope will be:<BR>\n" );
document.write( "L + 2W = 300<BR>\n" );
document.write( "L = (300-2W); use this form for substitution in the area equation<BR>\n" );
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document.write( "A = L * W<BR>\n" );
document.write( "Replace L with (300-2W)<BR>\n" );
document.write( "A = W(300-2W)<BR>\n" );
document.write( "A = -2W^2 + 300W<BR>\n" );
document.write( "this is a quadratic equation, max area occurs at the axis of symmetry which we can find with formula x = -b/(2a), in this equation it's<BR>\n" );
document.write( "W = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-300%29%2F%282%2A-2%29 ALIGN=MIDDLE  ALT=\"%28-300%29%2F%282%2A-2%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "W = <IMG STYLE=\"max-width:80%;\" SRC=/cgi-bin/plot-formula.mpl?expression=%28-300%29%2F-4%29 ALIGN=MIDDLE  ALT=\"%28-300%29%2F-4%29\"   DISABLED_style= \"max-width:90%; height:auto;\" ><BR>\n" );
document.write( "W = +75 m is the width for max area<BR>\n" );
document.write( "then<BR>\n" );
document.write( "L = 300 - 2(75)<BR>\n" );
document.write( "L = 300 - 150<BR>\n" );
document.write( "L = 150 m is the length<BR>\n" );
document.write( "Find the area<BR>\n" );
document.write( "150 * 75 = 11,250 sq/m is the max area with 300 ft of rope<BR>\n" );
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document.write( "How about this? Are you understanding this now? </SPAN>\n" );
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