document.write( "Question 61975: the perimeter of a rectangle is 82 yards. The width is 15 yards less than the length. Find the lenght and the width of the rectangle. \n" ); document.write( "
Algebra.Com's Answer #42819 by 303795(602)\"\" \"About 
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Call the length of the rectangle l. the width is 15 yards less than the length so the width is l - 15.\r
\n" ); document.write( "\n" ); document.write( "The perimeter of the rectangle = length + length + width + width\r
\n" ); document.write( "\n" ); document.write( "Using the length (l) and width (l - 15) then the perimeter can be found by\r
\n" ); document.write( "\n" ); document.write( "Perimeter = l + l + l -15 + l - 15 = 4l - 30\r
\n" ); document.write( "\n" ); document.write( "This equals 82 yards so\r
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\n" ); document.write( "\n" ); document.write( "4l - 30 = 82 Add 30 to each side of the equation\r
\n" ); document.write( "\n" ); document.write( "4l = 82+30 = 112\r
\n" ); document.write( "\n" ); document.write( "4l = 112 Divide each side of the equation by 4\r
\n" ); document.write( "\n" ); document.write( "l = 112 / 4 = 28 Yards\r
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\n" ); document.write( "\n" ); document.write( "The width is 15 less than this ie 28 - 15 = 13 Yards\r
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\n" ); document.write( "\n" ); document.write( "(Be careful with the letter l which I have used in the example. It can look like a number one.)
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