document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=62064>Question 62064</A>: <I><SPAN STYLE=\"word-break: break-all;\"> I have no idea how to work this problem, could someone help me?\r<BR>\n" );
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document.write( "In an amplifier, the power gain P is given by the function:<BR>\n" );
document.write( "P= 10 log Pout/Pin\r<BR>\n" );
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document.write( "where Pin is the power input in watts and Pout is the power output in watts. If an amplififier has a power gain of 10 watts and the output power is 7 watts, find the input power. <BR>\n" );
document.write( "(added note the out and in words next to the P are suppose to be lower than the P, but I don't know how to show it on here. so it would be the opposite of using the ^ sign to do what I mean.) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #42818 by </B><A HREF=/tutors/aboutme.mpl?userid=Nate><B>Nate(3500)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Nate><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=42818\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> P = 10*log(Pout / Pin)<BR>\n" );
document.write( "10 = 10*log(7/Pin)<BR>\n" );
document.write( "1 = log(7/Pin)<BR>\n" );
document.write( "10 = 7/Pin<BR>\n" );
document.write( "10*Pin = 7<BR>\n" );
document.write( "Pin = 7/10 = 0.7 </SPAN>\n" );
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