document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=694738>Question 694738</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The terminal side of an angle theta in standard position coincides with the line 4x + y=0 in Quadrant II. sec theta to the nearest thousandth. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #428158 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=428158\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The terminal side of an angle theta in standard position coincides with the line 4x + y=0 in Quadrant II. sec theta to the nearest thousandth.<BR>\n" );
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document.write( "Let x = -1, then y = 4<BR>\n" );
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document.write( "Solve for \"r\":<BR>\n" );
document.write( "r = sqrt[x^2+y^2] = sqrt(1+16) = sqrt(17)<BR>\n" );
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document.write( "sec(theta) = r/x = -sqrt(17)<BR>\n" );
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document.write( "cos(theta) = -1/sqrt(17) = -0.2425..<BR>\n" );
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document.write( "theta = cos^-1(-0.2425356..) = 104.036.. degrees<BR>\n" );
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document.write( "Cheers,<BR>\n" );
document.write( "Stan H. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );