document.write( "Question 694747: a bus travel at 36 km per hour and arrive its destination half an hour late if the bus travel at 42 km per hour and it arrives at its destination half an hour earlier find the distance \n" ); document.write( "

Algebra.Com's Answer #428155 by sachi(548) $\"\"$ $\"About$

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let the distance is s km
\n" ); document.write( "the time taken at 36 km/hr speed =s/36 hr
\n" ); document.write( "the time taken at 42 km/hr speed =s/42 hr
\n" ); document.write( "the difference between two times= s/36-s/42=1 (1/2hr late+1/2 hr earlier=1 hr)
\n" ); document.write( "or s(42-36)=42*36
\n" ); document.write( "or s=42*36/6=252 km \n" ); document.write( "

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