document.write( "Question 694690: find three consecutive integers such that the first added to 5 times the second exceeds 3 times the last by 51. \n" ); document.write( "

Algebra.Com's Answer #428137 by 55305(86) $\"\"$ $\"About$

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First lets assume the three number are n-1,n,and n+1, since the numbers are consecutive integers. Our equation would be
\n" ); document.write( " $\"%28n-1%29%2B+5%2An=+3%28n%2B1%29%2B51\"$ , which simplifies to
\n" ); document.write( " $\"6%2An-1=3%2An%2B54\"$ . Now we can solve by subtracting 3n and adding 1 to each side:
\n" ); document.write( " $\"3%2An=55\"$
\n" ); document.write( "that would mean that n is not an integer, and there are no consecutive integers which have those properties.
\n" ); document.write( "Numbers that work out that differ by 1 are $\"52%2F3\"$ $\"55%2F3\"$ $\"58%2F3\"$
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