document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=694640>Question 694640</A>: <I><SPAN STYLE=\"word-break: break-all;\"> (sin^2x+cos^2x)/ cosx = secx </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #428136 by </B><A HREF=/tutors/aboutme.mpl?userid=sachi><B>sachi(548)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sachi><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=sachi><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=428136\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> the question is actually (sin^2x+cos^2x)/cosx=secx<BR>\n" );
document.write( "or 1/cosx=secx (as sin^2x+cos^2x=1 always) </SPAN>\n" );
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