document.write( "Question 694674: A canoeist paddled for 4 hours with a 6-km/h current to reach a campsite. The return trip against the same current took 10 hours. Find the speed of the canoe in still water. \n" ); document.write( "
Algebra.Com's Answer #428133 by mananth(16946)![]() ![]() You can put this solution on YOUR website! canoe speed x km/h \n" ); document.write( "current speed 6 km/h \n" ); document.write( ".. \n" ); document.write( "against currentspeed x- 6 \n" ); document.write( "withcurrent x+ 6 \n" ); document.write( ".. \n" ); document.write( "Against current 10 hours \n" ); document.write( "with current x+y 4 hours \n" ); document.write( "Distance is same. D=r*t \n" ); document.write( "10 ( x - 6 ) = 4 ( x + 6 ) \n" ); document.write( "10 x - 60 = 4 x + 24 \n" ); document.write( "10 x - 4 x = 60 + 24 \n" ); document.write( "6 x = 84 \n" ); document.write( "/ 6 \n" ); document.write( "x = 14 km/h \n" ); document.write( "canoe = 14 km/h \n" ); document.write( " \n" ); document.write( " |