document.write( "Question 694674: A canoeist paddled for 4 hours with a 6-km/h current to reach a campsite. The return trip against the same current took 10 hours. Find the speed of the canoe in still water. \n" ); document.write( "
Algebra.Com's Answer #428133 by mananth(16946)\"\" \"About 
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canoe speed x km/h
\n" ); document.write( "current speed 6 km/h
\n" ); document.write( "..
\n" ); document.write( "against currentspeed x- 6
\n" ); document.write( "withcurrent x+ 6
\n" ); document.write( "..
\n" ); document.write( "Against current 10 hours
\n" ); document.write( "with current x+y 4 hours
\n" ); document.write( "Distance is same. D=r*t
\n" ); document.write( "10 ( x - 6 ) = 4 ( x + 6 )
\n" ); document.write( "10 x - 60 = 4 x + 24
\n" ); document.write( "10 x - 4 x = 60 + 24
\n" ); document.write( "6 x = 84
\n" ); document.write( "/ 6
\n" ); document.write( "x = 14 km/h
\n" ); document.write( "canoe = 14 km/h
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