document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=694692>Question 694692</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The sum of the digits of a two-digit number is 12. If the digits are reversed, the new number is 18 less than the original number. Find the original number. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #428129 by </B><A HREF=/tutors/aboutme.mpl?userid=sachi><B>sachi(548)</B></A><img src=\"/images/stars/stars-10.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=sachi><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=sachi><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=428129\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> The sum of the digits of a two-digit number is 12.<BR>\n" );
document.write( " let the ones digit is x then tens digit is 12-x<BR>\n" );
document.write( " then the no is 10(12-x)+x........original no<BR>\n" );
document.write( " If the digits are reversed, <BR>\n" );
document.write( " the no is 10x+(12-x)...........new no<BR>\n" );
document.write( " the new number is 18 less than the original number.<BR>\n" );
document.write( " so 10x+(12-x)=10(12-x)+x-18<BR>\n" );
document.write( " or 9x+12=102-9x<BR>\n" );
document.write( " or 18x=102-12=90<BR>\n" );
document.write( " or x=5 is the ones digit <BR>\n" );
document.write( " so the tens digit ig 12-5=7<BR>\n" );
document.write( " so the original number is 75 </SPAN>\n" );
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