document.write( "Question 694592: The radiator of a car is filled with 3.8L of a solution of 45% antifreeze. How much of the solution should be drained and replaced with antifreeze to increase the concentration of antifreeze to 60%? Round to the nearest tenth of liter. \r
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document.write( "I tried the problem and got it wrong. I did:\r
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document.write( "3.8L/1=45%/60% = 2.9L \n" );
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Algebra.Com's Answer #428104 by josmiceli(19441)![]() ![]() You can put this solution on YOUR website! You start with 3.8 liters and end with 3.8 liters \n" ); document.write( "This is one of the keys. \n" ); document.write( " \n" ); document.write( "Let \n" ); document.write( "with pure antifreeze \n" ); document.write( " \n" ); document.write( "----------------------------------------- \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "1.036 liters of the solution should be drained and \n" ); document.write( "replaced with pure antifreeze \n" ); document.write( "----------------- \n" ); document.write( "check: \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Did I get it right?\r \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " \n" ); document.write( " |