document.write( "Question 694592: The radiator of a car is filled with 3.8L of a solution of 45% antifreeze. How much of the solution should be drained and replaced with antifreeze to increase the concentration of antifreeze to 60%? Round to the nearest tenth of liter. \r
\n" ); document.write( "\n" ); document.write( "I tried the problem and got it wrong. I did:\r
\n" ); document.write( "\n" ); document.write( "3.8L/1=45%/60% = 2.9L
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Algebra.Com's Answer #428104 by josmiceli(19441)\"\" \"About 
You can put this solution on YOUR website!
You start with 3.8 liters and end with 3.8 liters
\n" ); document.write( "This is one of the keys.
\n" ); document.write( "\"+.45%2A3.8+=+1.71+\" liters of pure antifreeze to start with
\n" ); document.write( "Let \"+x+\" = liters to be drained off and replaced
\n" ); document.write( "with pure antifreeze
\n" ); document.write( "\"+.45x+\" = liters of pure antifreeze drained off.
\n" ); document.write( "-----------------------------------------
\n" ); document.write( "\"+%28+1.71+-+.45x+%2B+x+%29+%2F+3.8+=+.6+\"
\n" ); document.write( "\"+1.71+%2B+.55x+=+.6%2A3.8+\"
\n" ); document.write( "\"+1.71+%2B+.55x+=+2.28+\"
\n" ); document.write( "\"+.55x+=+2.28+-+1.71+\"
\n" ); document.write( "\"+.55x+=+.57+\"
\n" ); document.write( "\"+x+=+1.0364+\"
\n" ); document.write( "1.036 liters of the solution should be drained and
\n" ); document.write( "replaced with pure antifreeze
\n" ); document.write( "-----------------
\n" ); document.write( "check:
\n" ); document.write( "\"+%28+1.71+-+.45x+%2B+x+%29+%2F+3.8+=+.6+\"
\n" ); document.write( "\"+%28+1.71+-+.45%2A1.0364+%2B+1.0364+%29+%2F+3.8+=+.6+\"
\n" ); document.write( "\"+1.71+-+.4662+%2B+1.036+=+.6%2A3.8+\"
\n" ); document.write( "\"+1.71+%2B+.5700+=+2.28+\"
\n" ); document.write( "\"+2.28+=+2.28+\"
\n" ); document.write( "Did I get it right?\r
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