document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=694592>Question 694592</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The radiator of a car is filled with 3.8L of a solution of 45% antifreeze. How much of the solution should be drained and replaced with antifreeze to increase the concentration of antifreeze to 60%? Round to the nearest tenth of liter. \r<BR>\n" );
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document.write( "I tried the problem and got it wrong. I did:\r<BR>\n" );
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document.write( "3.8L/1=45%/60% = 2.9L </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #428097 by </B><A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><B>ankor@dixie-net.com(22740)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=ankor@dixie-net.com><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=ankor@dixie-net.com><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=428097\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\">  The radiator of a car is filled with 3.8L of a solution of 45% antifreeze.<BR>\n" );
document.write( " How much of the solution should be drained and replaced with antifreeze to increase the concentration of antifreeze to 60%?<BR>\n" );
document.write( " Round to the nearest tenth of liter. <BR>\n" );
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document.write( "Use this equation:<BR>\n" );
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document.write( "Let x = amt to be removed and then added<BR>\n" );
document.write( ".45(3.8-x) + 1x = .60(3.8) </SPAN>\n" );
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