document.write( "Question 694483: Nerio is now 2 years younger than Jean, while Angel is one year younger than Mon. If the sum of Mon's Age in 3 years, Jean's age 2 years ago, and Angel's age next year is 78, find their present ages.\r
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Algebra.Com's Answer #428096 by ankor@dixie-net.com(22740)![]() ![]() You can put this solution on YOUR website! Nerio is now 2 years younger than Jean, \n" ); document.write( "n = j-2 \n" ); document.write( ": \n" ); document.write( "while Angel is one year younger than Mon. \n" ); document.write( "a = m-1 \n" ); document.write( ": \n" ); document.write( "If the sum of Mon's Age in 3 years, Jean's age 2 years ago, and Angel's age next year is 78, \n" ); document.write( "(m+3) + (j-2) + (a+1) = 78 \n" ); document.write( "m + j + a + 4 = 78 \n" ); document.write( "m + j + a = 78 - 4 \n" ); document.write( "m + j + a = 74 \n" ); document.write( "m + j + (m-1) = 74 \n" ); document.write( "2m + j = 74 + 1 \n" ); document.write( "2m + j = 75 \n" ); document.write( ": \n" ); document.write( "This about all you can do with this, Where does Nerio appear in this problem?\r \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "\n" ); document.write( " find their present ages. \n" ); document.write( " |