document.write( "Question 694483: Nerio is now 2 years younger than Jean, while Angel is one year younger than Mon. If the sum of Mon's Age in 3 years, Jean's age 2 years ago, and Angel's age next year is 78, find their present ages.\r
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Algebra.Com's Answer #428096 by ankor@dixie-net.com(22740)\"\" \"About 
You can put this solution on YOUR website!
Nerio is now 2 years younger than Jean,
\n" ); document.write( "n = j-2
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\n" ); document.write( "while Angel is one year younger than Mon.
\n" ); document.write( "a = m-1
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\n" ); document.write( "If the sum of Mon's Age in 3 years, Jean's age 2 years ago, and Angel's age next year is 78,
\n" ); document.write( "(m+3) + (j-2) + (a+1) = 78
\n" ); document.write( "m + j + a + 4 = 78
\n" ); document.write( "m + j + a = 78 - 4
\n" ); document.write( "m + j + a = 74
\n" ); document.write( "m + j + (m-1) = 74
\n" ); document.write( "2m + j = 74 + 1
\n" ); document.write( "2m + j = 75
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\n" ); document.write( "This about all you can do with this, Where does Nerio appear in this problem?\r
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\n" ); document.write( "\n" ); document.write( " find their present ages.
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