document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=694541>Question 694541</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The altitude of a triangle is 2 metres longer than its base what are the dimensions of the altitude and the base if the area of the triangle is 40 metres squared.\r<BR>\n" );
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document.write( "can you please help me I don't understand this. Thanks in advance :) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #428091 by </B><A HREF=/tutors/aboutme.mpl?userid=mananth><B>mananth(16946)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=mananth><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=mananth><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=428091\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Area of triangle = (1/2) *base * altitude\r<BR>\n" );
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document.write( "let base be x m<BR>\n" );
document.write( "altitude = (x+2) m\r<BR>\n" );
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document.write( "Area = (1/2) *x*(x+2)\r<BR>\n" );
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document.write( "40= (1/2) *x^2+2x<BR>\n" );
document.write( "80=x^2+2x\r<BR>\n" );
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document.write( "x^2+2x-80=0\r<BR>\n" );
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document.write( "x^2+10x-8x-80=0\r<BR>\n" );
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document.write( "x(x+10)-8(x+10)=0<BR>\n" );
document.write( "(x+10)(x-8)=0<BR>\n" );
document.write( "x=-10, OR 8\r<BR>\n" );
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document.write( "length cannot be negative<BR>\n" );
document.write( "so base = 8m<BR>\n" );
document.write( "Altitude = 8+2 = 10 m </SPAN>\n" );
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