document.write( "Question 694596: what is the value for y when 5y^2-12y+35=0?
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Algebra.Com's Answer #428042 by jim_thompson5910(35256)\"\" \"About 
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\"y+=+%28-b%2B-sqrt%28b%5E2-4ac%29%29%2F%282a%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"y+=+%28-%28-12%29%2B-sqrt%28%28-12%29%5E2-4%285%29%2835%29%29%29%2F%282%285%29%29\" Plug in \"a+=+5\", \"b+=+-12\", \"c+=+35\"\r
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\n" ); document.write( "\n" ); document.write( "\"y+=+%2812%2B-sqrt%28144-%28700%29%29%29%2F%2810%29\"\r
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\n" ); document.write( "\n" ); document.write( "\"y+=+%2812%2B-sqrt%28-556%29%29%2F10\"\r
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\n" ); document.write( "\n" ); document.write( "\"y+=+%2812%2Bsqrt%28-556%29%29%2F10\" or \"y+=+%2812-sqrt%28-556%29%29%2F10\"\r
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\n" ); document.write( "\n" ); document.write( "\"y+=+%2812%2B2i%2Asqrt%28139%29%29%2F10\" or \"y+=+%2812-2i%2Asqrt%28139%29%29%2F10\"\r
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\n" ); document.write( "\n" ); document.write( "\"y+=+%286%2Bi%2Asqrt%28139%29%29%2F5\" or \"y+=+%286-i%2Asqrt%28139%29%29%2F5\"
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