document.write( "Question 694528: log base 1/5 ((x^2)+x) - log base 1/5 ((x^2)-x) = -2\r
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Algebra.Com's Answer #428015 by stanbon(75887)\"\" \"About 
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log base 1/5 ((x^2)+x) - log base 1/5 ((x^2)-x) = -2
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\n" ); document.write( "log1/5[(x^2+x)/(x^2-x)] = -2
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\n" ); document.write( "(x^2+x)/(x^2-x) = (1/5)^-2
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\n" ); document.write( "(x+1)/(x-1) = 25
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\n" ); document.write( "x+1 = 25x-25
\n" ); document.write( "24x = 26
\n" ); document.write( "x = 13/12
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\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
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