document.write( "Question 694528: log base 1/5 ((x^2)+x) - log base 1/5 ((x^2)-x) = -2\r
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Algebra.Com's Answer #428015 by stanbon(75887) ![]() You can put this solution on YOUR website! log base 1/5 ((x^2)+x) - log base 1/5 ((x^2)-x) = -2 \n" ); document.write( "------------------ \n" ); document.write( "log1/5[(x^2+x)/(x^2-x)] = -2 \n" ); document.write( "------------------ \n" ); document.write( "(x^2+x)/(x^2-x) = (1/5)^-2 \n" ); document.write( "----- \n" ); document.write( "(x+1)/(x-1) = 25 \n" ); document.write( "----- \n" ); document.write( "x+1 = 25x-25 \n" ); document.write( "24x = 26 \n" ); document.write( "x = 13/12 \n" ); document.write( "================ \n" ); document.write( "Cheers, \n" ); document.write( "Stan H. \n" ); document.write( "================ \n" ); document.write( " \n" ); document.write( " |