document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=694538>Question 694538</A>: <I><SPAN STYLE=\"word-break: break-all;\"> two trains traveling on parallel tracks leave Tucson at the same time. In 6 hours the faster train is 382 mile from Tucson and the trains are 112 miles apart. Find how fast each train is traveling. </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #428001 by </B><A HREF=/tutors/aboutme.mpl?userid=Ave><B>Ave(106)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Ave><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Ave><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=428001\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Faster train went 382 miles in 6 hours. use distance=rate*time to find r(rate or mph)<BR>\n" );
document.write( "d=rt<BR>\n" );
document.write( "382=6r divide both sides by 6<BR>\n" );
document.write( "63.6666=r round\r<BR>\n" );
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document.write( "* 63.7 mph for faster train\r<BR>\n" );
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document.write( "Slower train was 112 miles behind the faster train. So 382 minus 112 miles for distance, in 6 hours. do the same thing<BR>\n" );
document.write( "d=rt<BR>\n" );
document.write( "382-112=6r<BR>\n" );
document.write( "270=6r<BR>\n" );
document.write( "45=r\r<BR>\n" );
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document.write( "* 45 mph for slower train </SPAN>\n" );
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