document.write( "Question 694400: Hey I was hoping you could help me out. My math problem is the following.
\n" ); document.write( "9x^2+25^2=1. I understand that this is the formula for an ellipse, but I am unaware of how to proceed with finding the vertices, the foci, and how to graph it. Am I supposed to divide both side by 9 and 25 to achieve x^2/a+y^2/b=1? My problem is making the right side equal out to 1. Thanks for any help!
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Algebra.Com's Answer #427956 by KMST(5328)\"\" \"About 
You can put this solution on YOUR website!
You probably meant
\n" ); document.write( "\"9x%5E2%2B25y%5E2=1\"
\n" ); document.write( "and want to express it in the form
\n" ); document.write( "\"x%5E2%2Fa%5E2%2By%5E2%2Fb%5E2=1\",
\n" ); document.write( "which is appropriate for an ellipse centered at the origin, with axes along the x- and y-axes.
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\n" ); document.write( "You could write your equation as
\n" ); document.write( "\"x%5E2%2F%281%2F9%29%2By%5E2%2F%281%2F25%29=1\" or as \"x%5E2%2F%281%2F3%29%5E2%2By%5E2%2F%281%2F5%29%5E2=1\"
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\n" ); document.write( "Even without re-writing the equation, it was obvious that it was the equation for an ellipse centered at the origin, with axes along the x- and y-axes, because there were no terms in \"x\" or \"y\", or \"xy\".
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\n" ); document.write( "VERTICES:
\n" ); document.write( "The vertices, then, are the intersections with the x- and y-axes, were \"y=0\" and \"x=0\", and those are points you need to graph the ellipse.
\n" ); document.write( "\"y=0\" --> \"9x%5E2=1\" --> \"x%5E2=1%2F9\" --> \"x+=1%2F3\" or \"x=-1%2F3\" gives you vertices (-1/3,0) and (1/3,0).
\n" ); document.write( "\"x=0\" --> \"25y%5E2=1\" --> \"y%5E2=1%2F25\" --> \"y=1%2F5\" or \"x=-1%2F5\" gives you co-vertices (0,-1/5) and (0,1/5).
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\n" ); document.write( "AXES:
\n" ); document.write( "Vertices (-1/3,0) and (1/3,0) are farther from center (0,0) than co-vertices (0,-1/5) and (0,1/5):
\n" ); document.write( "\"1%2F3%3E1%2F5\",
\n" ); document.write( "so the segment between (-1/3,0) and (1/3,0) is called the major axis,
\n" ); document.write( "and the segment/distance from each of those vertices to the center is called the semi-major axis, represented as \"a\",
\n" ); document.write( "so \"a=1%2F3\".
\n" ); document.write( "The distance from the center to the co-vertices is the semi-minor axis:
\n" ); document.write( "\"b=1%2F5\".
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\n" ); document.write( "FOCI:
\n" ); document.write( "The foci would be useful to draw the ellipse if you wanted a very accurate representation.
\n" ); document.write( "They are points on both semi-major axes at a distance from the center called the focal distance, represented as \"c\".
\n" ); document.write( "Since for all points of the ellipse the sum of the distances to the foci is constant, the same.
\n" ); document.write( "For the vertices, the distance to the nearest focus is \"a-c\" and the distance to the other one is \"a%2Bc\", so the sum is \"2a\".
\n" ); document.write( "For the co-vertices, the distance to each focus in the hypotenuse of a right triangle with leg lengths \"b\" and \"c\".
\n" ); document.write( "Each of those distances is \"sqrt%28b%5E2%2Bc%5E2%29\", so the sum is \"2sqrt%28b%5E2%2Bc%5E2%29\".
\n" ); document.write( "Since that should be the same as for the vertices,
\n" ); document.write( "\"2a=2sqrt%28b%5E2%2Bc%5E2%29\" <--> \"a=sqrt%28b%5E2%2Bc%5E2%29\" --> \"highlight%28a%5E2=b%5E2%2Bc%5E2%29\"
\n" ); document.write( "That formula allows you to find the focal distance and graph the foci.
\n" ); document.write( "\"%281%2F3%29%5E2=%281%2F5%29%5E2%2Bc%5E2\" --> \"1%2F9=1%2F25%2Bc%5E2\" --> \"c%5E2=1%2F9-1%2F25\" --> \"c%5E2=%2825-9%29%2F225\" --> \"c%5E2=16%2F225\" --> \"highlight%28c=4%2F15%29\"
\n" ); document.write( "So the foci will be at (-4/15,0) and (4/15,0).
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\n" ); document.write( "GRAPHING:
\n" ); document.write( "We can plot the vertices co-vertices and foci, like this
\n" ); document.write( " Then draw the ellipse \"graph%28300%2C300%2C-0.4%2C0.4%2C-0.4%2C0.4%2C9x%5E2%2B25y%5E2%3C1%29\"
\n" ); document.write( "I would just draw a curve that passes through vertices and co-vertices and looks like it could be an ellipse.
\n" ); document.write( "To have a real ellipse, you would have to stick pins at the foci; make a loop of thread with a total length (all around) equal to the the distance between the foci, plus the distance between the vertices; throw the loop over the pins; stretch the loop with the tip of a pencil, and draw around keeping the loop fully stretched.
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