document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=694031>Question 694031</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Please help me answer this question: An Artifcat is discovered at a certain site. If it has 79% of the carbon-14 it originally contained, what is the approximate age of the artifact? (Carbon decays at the rate of 0.0125% annually) </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #427943 by </B><A HREF=/tutors/aboutme.mpl?userid=stanbon><B>stanbon(75887)</B></A><img src=\"/images/stars/stars-13.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=stanbon><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=427943\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> Artifact is discovered at a certain site. If it has 79% of the carbon-14 it originally contained, what is the approximate age of the artifact? (Carbon decays at the rate of 0.0125% annually)<BR>\n" );
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document.write( "Note: 1 - 0.000125 = 0.999875<BR>\n" );
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document.write( "0.79*Ao = Ao(0.999875)^t<BR>\n" );
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document.write( "0.999875)^t = 0.79<BR>\n" );
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document.write( "Take the log:<BR>\n" );
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document.write( "t = ln(0.79)/ln(0.999875) = 1886 yrs old<BR>\n" );
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document.write( "cheers,<BR>\n" );
document.write( "Stan H.<BR>\n" );
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