document.write( "Question 694445: Bear population. To estimate the size of the bear population on the Keweenaw Peninsula, conservationists captured, tagged, and released 50 bears. One year later, a random sample of 100 bears included only 2 tagged bears. What is the conservationist's estimate of the size of the bear population?
\n" ); document.write( " To estimate the size of the bear population on the Keweenaw Peninsula, conservationists captured, tagged, and released 50 bears. One year later, a random sample of 100 bears included only 2 tagged bears. What is the conservationist's estimate of the size of the bear population? Let \"x\" be the number in the population. Real population / sample caught = released population / sample caught.
\n" ); document.write( "x/100=50/2
\n" ); document.write( "x=2500 bears
\n" ); document.write( "Tagged by conservationists = 50 bears which represented an estimated 2% of the population = 50/.02=2500 total bear population.\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "Page 437 problem 56 and Page 444 problem 10
\n" ); document.write( "Problem: 10 pg. 444
\n" ); document.write( "For the second problem in this assignment I am asked to solve this equation for y. The first thing I notice is that it is a single fraction (ratio) on both sides of the equal sign so basically it is a proportion which can be solved by cross multiplying the extremes and means.
\n" ); document.write( " \r
\n" ); document.write( "\n" ); document.write( " This is the proportion set up and ready to solve. I will cross multiply the x and y setting the extremes equal to the means.
\n" ); document.write( "(y-1)*4=(x+3)-(-3)
\n" ); document.write( "4y-4=-3x-9
\n" ); document.write( "4y=-3x-9+4
\n" ); document.write( "4y=-3x-5 Divide both sides by 4
\n" ); document.write( "4y = -3x – 5 Simplify
\n" ); document.write( " 4 4 4
\n" ); document.write( "4y = -(3) * x – 5
\n" ); document.write( " 4 (4) 4
\n" ); document.write( "y = -(3) * x-5 Answer to problem 10 on page 444.
\n" ); document.write( " (4) 4\r
\n" ); document.write( "
\n" ); document.write( "
\n" ); document.write( "\n" ); document.write( "IS THIS CORRECT OF THE WORK i PERFORMED SO FAR?
\n" ); document.write( "

Algebra.Com's Answer #427932 by stanbon(75887)\"\" \"About 
You can put this solution on YOUR website!
This is the proportion set up and ready to solve. I will cross multiply the x and y setting the extremes equal to the means.
\n" ); document.write( "(y-1)*4=(x+3)(-3)
\n" ); document.write( "4y-4=-3x-9
\n" ); document.write( "4y=-3x-9+4
\n" ); document.write( "4y=-3x-5 Divide both sides by 4
\n" ); document.write( "------
\n" ); document.write( "y = (-3/4)x - (5/4)
\n" ); document.write( "======================\r
\n" ); document.write( "\n" ); document.write( "Corrections made.
\n" ); document.write( "=================
\n" ); document.write( "Cheers,
\n" ); document.write( "Stan H.
\n" ); document.write( "=======================
\n" ); document.write( "
\n" );