document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=694252>Question 694252</A>: <I><SPAN STYLE=\"word-break: break-all;\"> The equation of the line that goes through the point (7,7) and is perpendicular to the line 2x+5y=4  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #427928 by </B><A HREF=/tutors/aboutme.mpl?userid=Ave><B>Ave(106)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Ave><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Ave><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=427928\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First put that equation in slope intercept so we can find the slope<BR>\n" );
document.write( "5y=-2x+4<BR>\n" );
document.write( "y=-2/5x+4/5<BR>\n" );
document.write( "Slope is -2/5, so the slope of a perpendicular line would be 5/2<BR>\n" );
document.write( "Now use point slope form to find the new equation<BR>\n" );
document.write( "y-y1=slope(x-x1) x1, and y1 are the points from (7,7)<BR>\n" );
document.write( "y-7=5/2(x-7)  multiply both sides by 2 to get rid of fraction<BR>\n" );
document.write( "2y-14=5x-35<BR>\n" );
document.write( "2y=5x-21<BR>\n" );
document.write( "----<BR>\n" );
document.write( "y=5/2x-21/2<- Answer in slope intercept form<BR>\n" );
document.write( "----<BR>\n" );
document.write( "-5x+2y=-21 <- Answer in standard form\r<BR>\n" );
document.write( "\n" );
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document.write( "</TD></TR></TABLE>\n" );