document.write( "Question 694199: Identify the center and foci of the ellipse. (x-2)^2/16 + (y-7)^2/169 =1 \n" ); document.write( "
Algebra.Com's Answer #427925 by lwsshak3(11628)\"\" \"About 
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Identify the center and foci of the ellipse. \"%28x-2%29%5E2%2F16+%2B+%28y-7%29%5E2%2F169+=1\"
\n" ); document.write( "This is an equation of an ellipse with vertical major axis.(y-denominator > x-denominator
\n" ); document.write( "Its standard form: \"%28x-h%29%5E2%2Fb%5E2%2B%28y-k%29%5E2%2Fa%5E2=1\", a>b, (h,k)=(x,y) coordinates of center
\n" ); document.write( "For given equation:
\n" ); document.write( "center: (2,7)
\n" ); document.write( "a^2=169
\n" ); document.write( "b^2=16
\n" ); document.write( "c^2=a^2-b^2=169/16=153
\n" ); document.write( "c=√153≈12.4
\n" ); document.write( "foci: (2,7±c)≈(2,7±12.4)≈(2,-5.4 and (2,19.4)
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