document.write( "Question 694390: graph y= 1/2(x-1)(x+2) \n" ); document.write( "

Algebra.Com's Answer #427916 by lwsshak3(11628) $\"\"$ $\"About$

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graph
\n" ); document.write( "y= 1/2(x-1)(x+2)
\n" ); document.write( "y=(1/2)(x^2+x-2)
\n" ); document.write( "complete the square:
\n" ); document.write( "y=(1/2)(x^2+x+1/4)-1-1/8
\n" ); document.write( "y=(1/2)(x+1/2)^2-9/8\r
\n" ); document.write( "\n" ); document.write( "This is an equation of a parabola that opens upwards.
\n" ); document.write( "Its standard form of equation:y=A(x-h)^2+k, (h,k)=(x,y) coordinates of the vertex
\n" ); document.write( "for given equation:y=(1/2)(x+1/2)^2-9/8
\n" ); document.write( "vertex: (-1/2,-9/8)
\n" ); document.write( "see graph below:
\n" ); document.write( " $\"+graph%28+300%2C+300%2C+-10%2C10%2C+-10%2C+10%2C%281%2F2%29%28x%2B.5%29%5E2-9%2F8%29+\"$ \n" ); document.write( "

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