document.write( "Question 7773: \"x%5E%281%2F2%29%2By=7\"
\n" ); document.write( "\"x%2By%5E%281%2F2%29=11\"
\n" ); document.write( "solve this equations for x and y
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Algebra.Com's Answer #4279 by khwang(438)\"\" \"About 
You can put this solution on YOUR website!
To solve:
\n" ); document.write( " \"x%5E%281%2F2%29%2By=7\" ...(1)
\n" ); document.write( "\"x%2By%5E%281%2F2%29=11\" ...(2)\r
\n" ); document.write( "\n" ); document.write( " From(1): x^(1/2) = 7 - y ,
\n" ); document.write( " Squaring both sides:
\n" ); document.write( " x = (7-y)^2 = y^2 - 14y + 49,
\n" ); document.write( " Goto (2): y^2 - 14y + 49 + y^(1/2) = 11,
\n" ); document.write( " Let w = y^1/2, so y = w^2,
\n" ); document.write( " so we have w^4 - 14 w^2 + w + 38 = 0,
\n" ); document.write( " Use syntheic division,we have
\n" ); document.write( " 1 + 0-14 + 1 + 38 (2
\n" ); document.write( " + 2 +4 -20 -38
\n" ); document.write( " ----------------------
\n" ); document.write( " 1 + 2 -10 -19 + 0\r
\n" ); document.write( "\n" ); document.write( " Hence,(w-2)(w^3 + 2w^2-10w -19) = 0.
\n" ); document.write( " Unfortunately, we cannot factor w^3 + 2w^2-10w -19,
\n" ); document.write( " and the three roots are in very bad form.
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\n" ); document.write( "Note,when w =2, y= 4 and x = 16 - 56 + 49 = 9
\n" ); document.write( " So, here I only give you one set of solution
\n" ); document.write( " x= 9 and y = 4.\r
\n" ); document.write( "\n" ); document.write( " Kenny
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