document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=694404>Question 694404</A>: <I><SPAN STYLE=\"word-break: break-all;\"> Solve. Round results to the nearest thousandth.<BR>\n" );
document.write( "2x^2+3x-7=0 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #427883 by </B><A HREF=/tutors/aboutme.mpl?userid=Waleak><B>Waleak(2)</B></A><img src=\"/images/stars/iconNewId_16x16.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Waleak><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Waleak><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=427883\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> There are no integers that when you add them make 3 and when you multiply them -7,so i'll use a formula to find out the roots and try to find the factored form.<BR>\n" );
document.write( "2x^2+3x-7=0<BR>\n" );
document.write( "a=2 b=3 C=-7 ac=-14<BR>\n" );
document.write( "D=b^2-4ac=9+56=65<BR>\n" );
document.write( "x1,x2=(-b almighty formula D)/20<BR>\n" );
document.write( "x1,2= (-3 almighty formula 65)/4<BR>\n" );
document.write( "x1=(-3- square root 65)/4<BR>\n" );
document.write( "x2=(-3+square root 65)/4<BR>\n" );
document.write( "well,i found the roots.so now,i will use this to find out the factured form<BR>\n" );
document.write( "a(x-x2)(x-x2)<BR>\n" );
document.write( "a=2<BR>\n" );
document.write( "x1=(-3-square root 65)/4<BR>\n" );
document.write( "x2=(-3+square root 65)/4<BR>\n" );
document.write( "2[x-(-3+square root 65)/4][x-(-3-square root 65)/4]<BR>\n" );
document.write( "This is the factured form. </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );