document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=694349>Question 694349</A>: <I><SPAN STYLE=\"word-break: break-all;\"> How do you write an equation of the line that passes through the point (6, 2) and is parallel to the line y = 1/2 x – 1 </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #427878 by </B><A HREF=/tutors/aboutme.mpl?userid=Ave><B>Ave(106)</B></A><img src=\"/images/stars/stars-09.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=Ave><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/cgi-bin/show-face.mpl?user=Ave><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=427878\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> use point slope form: <BR>\n" );
document.write( "y-y1=slope(x-x1) slope of parallel lines are equal so the slope is 1/2. x1 and y1 are the point coordinates (6,2)\r<BR>\n" );
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document.write( "y-2=1/2(x-6) times both sides by 2 to get rid of fraction<BR>\n" );
document.write( "2y-4=x-6 add 4 to both sides<BR>\n" );
document.write( "2y=x-2 divide by 2\r<BR>\n" );
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document.write( "y=1/2x-1\r<BR>\n" );
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document.write( "since it's the same equation there are no lines parallel, because the original line passes through (6,2)\r<BR>\n" );
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document.write( "If you wanted a perpendicular line going through (6,2) you would do the same thing except use -2 for the slope.\r<BR>\n" );
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