document.write( "<A HREF=/cgi-bin/jump-to-question.mpl?question=61991>Question 61991</A>: <I><SPAN STYLE=\"word-break: break-all;\"> 3x + y = 5 <BR>\n" );
document.write( "4x - 7y = -10  </SPAN>\n" );
document.write( "</I><HR><TABLE width=100%><TR><TD><B><A HREF=http://www.algebra.com/>Algebra.Com's</A> Answer #42786 by </B><A HREF=/tutors/aboutme.mpl?userid=hotrodd><B>hotrodd(18)</B></A><img src=\"/images/stars/stars-06.gif\" alt=\"\" >&nbsp;<A HREF=/tutors/aboutme.mpl?userid=hotrodd><IMG SRC=http://www.algebra.com/images/aboutme-small.gif BORDER=0 alt=\"About Me\" VALIGN=MIDDLE></A>&nbsp;<IMG SRC=http://www.algebra.com/images/nopicture.jpg><BR>You can <A HREF=\"/cgi-bin/embed-solution.mpl?show=1&solution=42786\">put this solution on YOUR website!</A><BR><SPAN STYLE=\"word-break: break-all;\"> First, multiply all of equation one by -2 so that both of the equations have the same answer. So you should have:<BR>\n" );
document.write( "-6x - 2y = -10<BR>\n" );
document.write( "4x - 7y = -10 <BR>\n" );
document.write( "Then, substitute the -10 in the first equation with 4x - 7y from the second equation:<BR>\n" );
document.write( "-6x - 2y = 4x - 7y<BR>\n" );
document.write( "Next, add 6x and 7y to both sides of the equation:<BR>\n" );
document.write( "5y = 10x<BR>\n" );
document.write( "Now, divide both sides of the equation by 5 to get:<BR>\n" );
document.write( "y = 2x<BR>\n" );
document.write( "Substitute 2x with the y in equation #1:<BR>\n" );
document.write( "3x + 2x = 5<BR>\n" );
document.write( "Combine like terms:<BR>\n" );
document.write( "5x = 5<BR>\n" );
document.write( "Divide each side by 5<BR>\n" );
document.write( "x = 1<BR>\n" );
document.write( "Now, substitute 1 for the x in equation #1:<BR>\n" );
document.write( "3(1) + y = 5<BR>\n" );
document.write( "Subtract each side by 3:<BR>\n" );
document.write( "y = 2\r<BR>\n" );
document.write( "\n" );
document.write( "YOUR ENDING ANSWER IS x = 1 AND y = 2 </SPAN>\n" );
document.write( "</TD></TR></TABLE>\n" );