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document.write( "mandy begins bicycling west at 30 miles per hour at 11:00 a.m. if liz leaves from the same point 20 minutes later bicycling west at 36 miles per hour, when will she catch mandy? \n" );
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Algebra.Com's Answer #427859 by checkley79(3341)![]() ![]() ![]() You can put this solution on YOUR website! D=RT \n" ); document.write( "MANDY=30T \n" ); document.write( "LIZ=36(T-1/3) \n" ); document.write( "THE DISTANCES ARE EQUAL. \n" ); document.write( "30T=36(T-1/3) \n" ); document.write( "30T=36T+36(-1/3) \n" ); document.write( "30T=36T-12 \n" ); document.write( "30T-36T=-12 \n" ); document.write( "-6T=-12 \n" ); document.write( "T=-12/-6 \n" ); document.write( "T=2 HOUR THEY WILL MEET. \n" ); document.write( "PROOF: \n" ); document.write( "30*2=36(2-1/3) \n" ); document.write( "60=36(1 2/3) \n" ); document.write( "60=36*5/3 \n" ); document.write( "60=180/3 \n" ); document.write( "60=60 \n" ); document.write( " \n" ); document.write( " |