document.write( "Question 694338: a train leaves a station and travels north at a speed of 75mph. four hours later, a second train leaves on a parallel track and travels north at 175mph. how far from the station will they meet. \n" ); document.write( "
Algebra.Com's Answer #427842 by MathTherapy(10552)\"\" \"About 
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a train leaves a station and travels north at a speed of 75mph. four hours later, a second train leaves on a parallel track and travels north at 175mph. how far from the station will they meet.\r
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\n" ); document.write( "\n" ); document.write( "Let distance from station be D
\n" ); document.write( "Time taken by 1st train to travel to \"meeting\" point, equals time taken by 2nd train to travel to \"meeting\" point, plus 4, OR\r
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\n" ); document.write( "\n" ); document.write( "\"D%2F75+=+D%2F175+%2B+4\"
\n" ); document.write( "7D = 3D + 2,100 ------ Multiplying by LCD, 525
\n" ); document.write( "7D – 3D = 2,100
\n" ); document.write( "4D = 2,100
\n" ); document.write( "D, or distance from station = \"2100%2F4\", or \"highlight_green%28525%29\" miles\r
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\n" ); document.write( "\n" ); document.write( "You can do the check!!\r
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\n" ); document.write( "\n" ); document.write( "Send comments and “thank-yous” to “D” at MathMadEzy@aol.com
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