document.write( "Question 694287: There is a 3digit number in which the 2nd digit is the sum of the 1st and 3rd digit. Can you prove that the number is divisible by 11? \n" ); document.write( "
Algebra.Com's Answer #427826 by KMST(5328)![]() ![]() You can put this solution on YOUR website! Yes. \n" ); document.write( "As a matter of fact, that is the way to multiply a two digit number times 11. \n" ); document.write( "It is very easy, as long as the sum of those digits is less than 10. \n" ); document.write( "You just write the two digits, leaving some space in the middle, and then write the sum in that middle space. \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "Then, second (tens) digit = \n" ); document.write( "and the value of the 3-digit number is \n" ); document.write( " \n" ); document.write( " \n" ); document.write( "The 3-digit number in the problem is |