document.write( "Question 62015: P(x)=x^3-5x+2 it ask me to find all the real zeros of the polynomial \n" ); document.write( "
Algebra.Com's Answer #42781 by Nate(3500)![]() ![]() ![]() You can put this solution on YOUR website! Descarte's Rule of Signs: \n" ); document.write( "P(x) = (+) x^3 (+-) 0x^2 (-) 5x^1 (+) 2x^0 \n" ); document.write( "P(-x) = (-) x^3 (+-) 0x^2 (+) 5x^1 (+) 2x^0 \n" ); document.write( "Pos: 2 .. 0 \n" ); document.write( "Neg: 1 .. 1 \n" ); document.write( "Img: 0 .. 2 \n" ); document.write( "We now know that there is definetly a negative zero. \n" ); document.write( "P(x) = x^3 - 5x + 2 \n" ); document.write( "a = 1,2 \n" ); document.write( "b = 1 \n" ); document.write( "+- a/b = +- 1 and +- 2 \n" ); document.write( "Synthetic Division: \n" ); document.write( "2.|......1......0......-5......2...... \n" ); document.write( "............1......2......-1.......0 \n" ); document.write( "(x - 2)(x^2 + 2x - 1) = P(x) \n" ); document.write( "x^2 + 2x - 1 = 0 \n" ); document.write( "x^2 + 2x = 1 \n" ); document.write( "(x + 1)^2 = 2 \n" ); document.write( "x + 1 = +- sqrt(2) \n" ); document.write( "x = -1 +- sqrt(2) \n" ); document.write( "Zeros: \n" ); document.write( "x = 2 \n" ); document.write( "x = -1 + sqrt(2) \n" ); document.write( "x = -1 - sqrt(2) \n" ); document.write( " |